Question

How do you solve `ln 2x = -8`?

Answer 1

`x=(e^(-8))/2~~1.7*10^(-4)`

Explanation:

The relationship between the logartihm and exponential functions is:

`ln(x)=y harr e^y=x`

Therefore:

`ln(2x)=-8 rarr 2x=e^(-8) rarr x=(e^(-8))/2~~1.7*10^(-4)`