Question

How do you solve `abs(2x + 3) - 6 = 11`?

Answer 1

`x = 7` or `x = -10`

Explanation:

`|2x+3| = 17`

Method 1:
`2x+3 = 17, " if " 2x+3 > 0`
`x = 7`

`-(2x+3) = 17, " if " 2x+3 < 0`
`x = -10`

Method 2:
`(2x+3)^2 = 17^2`
`x^2 + 3x - 70 = 0`
`(x-7)(x+10) = 0`
`x = 7` or `x = -10`