Question

Question #690f9

Answer 1

`1.12dm^3`

Explanation:

We have 5.4g of `N_2O_5` which has an `M_r` of 108 (14x2) + (16x5).

Moles of `N_2O_5` = mass/`M_r` = 5.4/108 = 0.05 mol

The molar volume of a gas at STP = `22.4dm^3`
Thererfore the volume of 0.05 mol of the gas = 0.05 x 22.4 = `1.12dm^3`