Question

Question #59543

Answer 1

I suspect you cannot?

Explanation:

`int_0^oo ln(x)/(1+x^2)dx`
`=int_0^1 ln(x)/(1+x^2)dx + int_1^oo ln(x)/(1+x^2)dx`
and at least the first integral is improper, because it is "close" to `int_0^1 ln(x)/1`dx ?