Question

Question #7bc10

Answer 1

`sqrt3`

Explanation:

`9sqrt8 = 9sqrt(2^3) = 3^2*2^(3/2)`
`6sqrt6 = 3*2*sqrt(3*2) = 3^1*2^1*3^(1/2)*2^(1/2) = 3^(3/2)*2^(3/2)`

`therefore` `(9sqrt8) / (6sqrt6) = (3^2*2^(3/2))/(3^(3/2)*2^(3/2))`

`= (3^(2 - 3/2)) * (2^(3/2 - 3/2))`
`= 3^(1/2)*1 = 3^(1/2) =` `sqrt(3)`