Question

How do you differentiate `f(x) = tanx+cscx`?

Answer 1

`f'(x)=sec^2x-cscxcotx`

Explanation:

Take each individual derivative, then combine

`d/dx(tanx)=sec^2x`

`d/dx(cscx)=-cscxcotx`

`:.f'(x)=sec^2x-cscxcotx`