An electric toy car with a mass of #8 kg# is powered by a motor with a voltage of #5 V# and a current supply of #4 A#. How long will it take for the toy car to accelerate from rest to #8/3 m/s#?

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Answer 1 · 2018-07-31T00:36:17

#a =0.9375 m/s^2#

I tried this:

#V= J/C#
#J= kgm^2/s^2#
#A=C/s#

#(5J/C*4C/s)/(8kg*8/3m/s)=#

#(20J/s)/(64/3kgm/s)=#

#(20kgm^2/s^2*1/s)/(64/3kgm/s)=#

#(20kgm^2/s^3)/(64/3kgm/s)=#

#(20kgm^2)/s^3*(3s)/(64kgm)= 0.9375 m/s^2#