Question #f6d65
↳Redirected from
"Question #dc117"
Let #x# denote the value of the first angle
#x + 2x +114 = 180#
#=>3x+114-180#
#=>3x=66#
#=>x=22#
#=>2x+114=2*22+114=158#
Measure of the first angle (in degrees): #22#
Measure of the second angle (in degrees): #158#
Let's start by representing the first angle with the variable #x#. For the second angle, it will be #114# degrees larger #(+114)# than #2# times the measure of the first angle #(2x)#.
First angle #= x#
Second angle #= 2x+114#
We know the sum of both angles must be equal to #180# degrees, so we can make our equation now...
#x+2x+114= 180#
Combine like terms (#x# and #2x#) to get
#3x+114= 180#
Subtract #114# from both sides to get
#3x=66#
Divide both sides by #3# to isolate #x#. This gets us
#x=22#
It's important to realize what our solution for #x# means. We designated #x# as being equal to the measure of the first angle.
First angle #(x)= 22^@#
The second angle is #2x+114#, and since we know what #x# is, we can plug it in for this equation.
#2(22)+114= 44+114= 158#
Second angle #= 158^@#
To make sure our measures for the angles make sense, we just add them up and see if we get #180^@#.
#22^@+158^@ = 180^@#