Question

What is the derivative of `y=e^(3-2x)` ?

Answer 1

By Chain Rule,
`y'=-2e^{3-2x}`.

Recall:
Exponential Rule: `(e^x)'=e^x`
Chain Rule: `[f(g(x))]'=f'(g(x))cdot g'(x)`

Since `f(x)=e^x` and `g(x)=3-2x`, we have
`y'=e^{3-2x}cdot(-2)=-2e^{3-2x}`