How do I use the quadratic formula to solve #x^2+5x=-2#?

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Answer 1 · 2014-09-30T03:23:12

#ax^2+bx+c=0#

#x^2+5x=-2#

#x^2+5x+2=0#

#a=1, b=5, c=2#

Quadratic formula

#x=(-(5)+-sqrt((5)^2-4(1)(2)))/(2(1))#

#x=(-5+-sqrt(25-8))/2#

#x=(-5+-sqrt(17))/2#