Question

How do you evaluate the integral `int3^(x) dx`?

Answer 1

`int3^xdx=1/ln3 3^x+"c"`

Explanation:

We want to find `int3^xdx`.

Make the natural substitution `u=3^x` so `du=3^xln3dx`.

So

`int3^xdx=1/ln3int1du=1/ln3 u+"c"=1/ln3 3^x+"c"`