Question

How do you express `cos theta - sec theta + cot theta` in terms of `sin theta`?

Answer 1

`sqrt (1-sin^2 theta)/ sin theta - sin^2 theta /sqrt(1- sin^2 theta`

Explanation:

`cos theta - sec theta + cot theta` is

`cos theta- 1/cos theta + cos theta/ sin theta`

= `cos theta/ sin theta -sin^2 theta/ cos theta`

=`sqrt (1-sin^2 theta)/ sin theta - sin^2 theta /sqrt(1- sin^2 theta`