How do you solve #3(abs(x-1)+2)=30#?

Question

↳Redirected from "Question #19ea3"

1612 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-10T17:42:58

The solutions are #x = -7# and #x = 9#.

Starting with #3(|x-1|+2)=30#, first divide both sides by 3 to give:
#|x-1|+2=10#.

Subtract 2 from both sides to give:
#|x-1|=8#

Hence
#x-1=+-8#

Add 1 to both sides to get:
#x = +-8 + 1#

So #x=-8+1=-7# or #x=8+1=9#.