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How do you solve #7e^(2x) = 77#?

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1 Answer

A. S. Adikesavan

May 28, 2016

#x=ln 11/2=1.199#, nearly.

Explanation:

#e^(2x)=77/7=11#

Inversely, #2x=ln 11#. So, #x =ln 11/2=1.199#, nearly.

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