How do you solve the equation #1/2x^2-8=16#?

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Answer 1 · 2017-03-19T10:53:29

#"answer is "x=+-4sqrt 3#

#1/2 x^2-8=16#

#1/2 x^2=16+8#

#1/2 x^2=24#

#x^2=2*24#

#x^2=48#

#x^2=16*3#

#sqrt(x^2)=sqrt(16*3)#

#x=+-4sqrt 3#