Question

How do you write the trigonometric form of `6i`?

Answer 1

`= 6e^(i pi/2)`

Explanation:

This number sits on the positive y (imaginary) axis of the Argand diagram and has zero x (real) component. It has length 6.

We can say that:

`6i = 0 + 6 i = 6(cos (pi/2) + i sin (pi/2)) = 6e^(i pi/2)`