How I write this expression in terms of sines and/or cosines, and then simplify? 1+cosαtanαcscα/cscα

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Answer 1 · 2018-03-23T06:53:30

#1+sin alpha#

#1+cos alpha tan alpha csc alpha/csc alpha#

#1+(cos alpha × tan alpha × cancel(csc alpha))/ cancel(csc alpha)#

#1+ cos alpha × tan alpha color(blue)(rarr 1)#

# tan alpha= sin alpha/cos alpha color(blue)(rarr 2)#

Putting value of #tan alpha# from #color(blue)(2)# in #color(blue)(1)#

#1+ cos alpha × sin alpha/ cos alpha#

#1+ cancel(cos alpha) × sin alpha/ cancel(cos alpha)#

#1+ sin alpha#