What is the derivative of #f(x)=ln(tanx)#?
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"How do you find the derivative of #y=ln(5x)#?"
1 Answer
Nov 13, 2015
Use the chain rule.
Explanation:
# = 1/tanx (-sec^2x)#
Now use trigonometry:
# = -cotxsec^2x#
# = -cosx/sinx 1/cos^2x#
# = -1/sinx 1/cosx#
# = -cscx secx#
