What is the norm of #< -5 , -2, 4 >#?

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Topscooter
Dec 21, 2015

#sqrt(45)#

Explanation:

We're basically calculating the norm of the vector #OA = (-5,-2,4)#. So we apply the formula for any #M(x,y,z) in RR^3 : ||OM|| = sqrt(x^2 + y^2 + z^2)#.

Here, #||OA|| = sqrt((-5)^2 + (-2)^2 + 4^2) = sqrt(25 + 4 + 16) = sqrt(45)#

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